Ivashko became Rublev's rival in the second round at the St. Petersburg Open

Belarusian tennis player Ilya Ivashko defeated Serb Laszlo Djere at the start of the St. Petersburg Open.

The first round match ended with a score of 6: 3, 6: 2.

The 46th racket of the world in 1 hour 15 minutes made 2 aces and 4 breaks, making a mistake when serving once. His opponent has filed right through 4 times and made 4 double faults.

The next rival of Ivashko will be the current winner of the tournament, Russian Andrei Rublev.

In another meeting of the day, American Tommy Paul, 54th in the ATP rankings, beat Spaniard Pedro Portero 6: 3, 6: 2.

Now he will face the winner of the meeting between American Taylor Fritz and Finn Emil Ruusuvuori.

ATP 250. St. Petersburg Open. Saint-Petersburg, Russia). Hard. Prize fund – $ 863,705

Ilya Ivashko (Belarus) – Laszlo Dyere (Serbia) – 6: 3, 6: 2

Tommy Paul (USA) – Pedro Portero (Spain) – 6: 3, 6: 2

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