Gracheva finished her performance at the tournament in Luxembourg

Gracheva finished her performance at the tournament in Luxembourg0

Russian tennis player Varvara Gracheva was defeated by the representative of Luxembourg Mendy Minella in the first round of the WTA 250 category tournament.

The meeting ended in two sets with a score of 3: 6, 4: 6. The 77th racket of the world from Russia filed three times through and made two double faults. On account of the winner – nine aces and one double.

In the next round, Minella will meet with Alize Cornet from France.

WTA 250. Luxembourg. Hard. Prize fund – 189708 euros

Mendy Minella (Luxembourg, WC) – Varvara Gracheva (Russia) – 6: 3, 6: 4

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